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Advanced Math / Nonlinear functions Difficulty: Hard

fx= x - 14 x + 19

The function f is defined by the given equation. For what value of x does fx reach its minimum?

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Explanation

Choice D is correct. It's given that fx=x-14x+19, which can be rewritten as fx=x2+5x-266. Since the coefficient of the x2-term is positive, the graph of y=fx in the xy-plane opens upward and reaches its minimum value at its vertex. The x-coordinate of the vertex is the value of x such that fx reaches its minimum. For an equation in the form fx=ax2+bx+c, where a , b , and c are constants, the x-coordinate of the vertex is -b2a. For the equation fx=x2+5x-266, a=1, b=5, and c=-266. It follows that the x-coordinate of the vertex is -521, or -52. Therefore, fx reaches its minimum when the value of x is -52.

Alternate approach: The value of x for the vertex of a parabola is the x-value of the midpoint between the two x-intercepts of the parabola. Since it’s given that fx=x-14x+19, it follows that the two x-intercepts of the graph of y=fx in the xy-plane occur when x=14 and x=-19, or at the points 14,0 and -19,0. The midpoint between two points, x1,y1 and x2,y2, is x1+x22,y1+y22. Therefore, the midpoint between 14,0 and -19,0 is 14+-192,0+02, or -52,0. It follows that fx reaches its minimum when the value of x is -52.

Choice A is incorrect. This is the y-coordinate of the y-intercept of the graph of y=fx in the xy-plane.

Choice B is incorrect. This is one of the x-coordinates of the x-intercepts of the graph of y=fx in the xy-plane.

Choice C is incorrect and may result from conceptual or calculation errors.